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Divisibility Rules for 2, 3, 4, 5, 6, 8, 9, 10 and 11

Soln Date / Update:-

20-Jul-2025 02:47PM

Solution:-

1. Divisibility Rule of 1:- All Numbers are divisible by 1.

Ex:-  25,  30, 35, 85 

Div-1

2. Divisibility Rule of 2:- If the digit in the ones place is 0, 2, 4, 6, 8 of a number, then the number will be completly divisible by 2.

Ex:- 256, 5632, 5886, 2540 etc.

Div-2

3 Divisible Rule of 3:- If the sum of all digits of a number is divisible by 3 then the given number is completely divisible by 3.

Ex:-   (i) 231   

Sum of all digit = 2 + 3 + 1

= 6 and 6 is divisible by 3

then the number 231 is completely divisible by 3

Div-3

4. Divisibility Rule of 4:- If the last two digits of any given number are either 0 or divisible by 4, then the number will be completely divisible by 4.

Ex:- (i) 5484

Given Number = 5484

Last two digit = 84

= 84 is divisible by 4

then the given number 5484 completely divisible by 4.

Div-4

General & Competition Math (Vidyasagar) Ch-2: Formmula
General & Competition
General & Compitition Sub-Math (Oscer)
General & Competition Sub-Math (Vidyasagar)

General & Competition Math (Vidyasagar) Ch-2: Number System
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