Find the sum of the numbers divisible by 123 in between 1000 and 2000
Soln Date / Update:-24-Jul-2025 05:53PM
Solution:-
Exrecise - 2 ( B ) Real Numbers
Ex-10. Find the sum of the numbers divisible by 123 in between 1000 and 2000.
Solution:-
Smallest number 1000 and greatest number = 2000
1000 / 123 Get remainder = 16
1000 - 16 = 984 but less than 1000
So, Smallest number divisible by 123
1st Number = 984 + 123 = 1107
2nd number = 1107 + 123 = 1230
3rd number = 1230 + 123 = 1353
4th number = 1353 + 123 = 1476
5th number = 1476 + 123 = 1599
6th number = 1599 + 123 = 1722
7th number = 1722 + 123 = 1845
8th number = 1845 + 123 = 1968
9th number = 1968 + 123 = 2091 X not between 1000 to 2000
Sum Of numbers divisible by 123
= 1st number + 2nd number + 3rd number + 4th number + 5th number + 6th number + 7th number + 8th number
= 1107 + 1230 + 1353 + 1476 + 1599 + 1722 + 1845 + 1968
= 12300 Ans.
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