The sum of two numbers is 910 when one of the numbers is divided by 51 leaves 17 as quotient without any remainder when the other number is divided by 17
Soln Date / Update:-31-Jul-2025 01:19PM
Solution:-
Exrecise - 2 ( B ) Real Numbers
Q-13. The sum of two numbers is 910. when one of the numbers is divided by 51. leaves 17 as quotient without any remainder when the other number is divided by 17.
Solution:-
Let the numbers X and Y
1st Number = X
2nd Number = Y
A/Q, X + Y = 910 --------(i)
One of the number is divided by 51 leaves 17 as quotient
X = 51 * 17
X = 867
Putting the value of X in eq(i)
X + Y = 910
867 + Y = 910
Y = 910 - 867
Y = 43
Now,
Other number is divided by 17 then what remainder
43 / 17
Remainder = 9 Ans.
Solution image given below,
