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If the sum of two digits number and the number formed after interchanging the digits is 110 then find the number if the difference of their digits is 4

Soln Date / Update:-

08-Aug-2025 01:12PM

Solution:-

Exrecise - 2 ( B ) Real Numbers

Q-20. If the sum of two digits number and the number formed after interchanging the digits is 110 then find the number if the difference of their digits is 4.

Solution:-

Let the two digits x and y

Unit place number = X

Tens place number = 10Y

Then, Make Original Number = 10Y + X -------(i)

After interchanging the digits ,

Unit place number = Y

Tens place number = 10X

Then, Make nterchanging number = 10X + Y ----(ii)

A/Q, sum of original number + interchanging number = 110

Or, ( 10Y + X ) + ( 10X + Y ) 110

Or, 10Y + X + 10X + Y = 110

Or, 11X + 11Y = 110

Or, 11( X + Y ) 110

Or, X + Y = 110 / 11

X + Y = 10 ------(iii)

Difference of their digits = 4 [Given in Question]

X - Y = 4  ------(iv)

Sum Equation (iii) And Equation (iv)

2X = 14 

X = 7

Putting the value of X in Eq(iii)

X + Y = 10

7 + Y = 10

Y = 10 - 7

Y = 3

Now, Make Possible number,

10X + Y           10Y + X

10 * 3 + 7        =10 * 7 + 3

30 + 7              = 70 + 3

= 37 Ans.         = 73 Ans.

Solution image given Below,

VidyasagarCh-2(B),Q-20

 

General & Competition Math (Vidyasagar) Ch-2, Exercise-2(B)
General & Competition
General & Compitition Sub-Math (Oscer)
General & Competition Sub-Math (Vidyasagar)

General & Competition Math (Vidyasagar) Ch-2: Number System
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