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The sum of which four consecutive numbers is 398

Soln Date / Update:-

28-Jul-2025 09:41PM

Solution:-

Exrecise - 2 ( B ) Real Numbers

Q-3. The sum of which four consecutive numbers is 398.

Solution:-

Let the four consecutive numbers

1st consecutive no. = x

2nd consecutive no. = x + 1

3rd consecutive no. = x + 2

4th consecutive no. = x + 3

A/Q,    Sum of four consecutive no. = 398

x + x + 1 + x + 2 + x + 3 = 398

4x + 6 = 398

4x = 398 - 6

4x = 392

x = 392 / 4

x = 98

Hence,

1st consecutive number = x

= 98 Ans.

2nd consecutive no. = x + 1 

= 98 + 1 = 99 Ans.

3rd consecutive no. = x + 2

= 98 + 2 = 100 Ans.

4th consecutive no. = x + 3

= 98 + 3 = 101 Ans.

Vidyasagar Math Ch-2,Q-3

General & Competition Math (Vidyasagar) Ch-2, Exercise-2(B)
General & Competition
General & Compitition Sub-Math (Oscer)
General & Competition Sub-Math (Vidyasagar)

General & Competition Math (Vidyasagar) Ch-2: Number System
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